So this is taking this equation and plugging it into the quadratic formula -b+- (sqrt (b^2)-(4)ac)/2a so your A value is 1 B value is 3 and C value is -5 so it’s B&E
I think the top right 1 is linear
Top left is neither and bottom is exponential
Answer : <em>Equation of line is</em> y=Equation of line is y=
x+
Step-by-step explanation:
Theory :
Equation of line is given as y = mx + c.
Where, m is slope and c is y intercepted.
Slope of given line : y =
x+1 is m= 
We know that line : y =
x+1 is parallel to equation of target line.
therefore, slope of target line will be
.
we write equation of target line as y=
x+c
Now, It is given that target line passes through point ( -5,-2)
hence, point ( -5,-2) satisfy the target line's equation.
we get,
y=
x+c
-2=
-5+ c
-5=
+c
c= 
thus, Equation of line is y=Equation of line is y=
x+