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dybincka [34]
2 years ago
14

How much work, , must be done on a system to decrease its volume from 19.0 L to 11.0 L by exerting a constant pressure of 6.0 at

m?
w = ________ kJ
Chemistry
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:

Explanation:

w = 16.0KJ

your welcome for the answer let me know ifyou need anymore help.

mark me brainliest.

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Which one is radioactive?
MakcuM [25]
C, the one with the most neutrons
3 0
3 years ago
In the reaction between copper and silver nitrate, 95.3 g of silver and 82.9g of copper nitrate are produced. How much of each r
Nastasia [14]

Reaction

2AgNO₃  +  Cu ⇒ Cu(NO₃)₂  +  2Ag

mol silver (Ag): 95.3 : 108 g/mol = 0.882

mol  copper nitrate (Cu(NO₃)₂): 82.9 : 187.5 g/mol = 0.441

mol Ag = 2 x mol Cu(NO₃)₂, so 0.441 being the mole basis of the reactants

mol Cu = 0.441

mass Cu = 0.441 x 63.5 g/mol = 28 g

mol AgNO₃ = 0.882

mass AgNO₃ = 0.882 x 170 g/mol = 149.94 g

5 0
3 years ago
What color or colors of light are transmitted by a piece of yellow glass?
Artyom0805 [142]

Answer:

So combining blue with yellow light is like combining blue light with red and green light. The result of combining these three primary colors of light is to produce white light.

Explanation:

8 0
3 years ago
What is the standard entropy change for the reaction below? 2 CO(g) + 2 NO(g) → N2(g) + 2 CO2(g) S o (CO(g)) = 197.7 J/(mol·K) S
photoshop1234 [79]

Answer:

\Delta _RS^o=-230J/(mol*K)

Explanation:

Hello,

In this case, for the given chemical reaction:

2 CO(g) + 2 NO(g) \rightarrow N_2(g) + 2 CO_2(g)

The standard entropy change is computed by subtracting the products standard enthalpy and the reactants standard enthalpy considering each species stoichiometric coefficients:

\Delta _RS^o=S ^o_{N2(g)}+2S ^o_{CO2(g)}-2S ^o_{CO(g)}-2S ^o_{NO(g)}\\\\\Delta _RS^o=191.6J/(mol*K)+2*213.8J/(mol*K) -2*213.8J/(mol*K) -2*210.8J/(mol*K)\\\\\Delta _RS^o=-230J/(mol*K)

Best regards.

3 0
3 years ago
Read 2 more answers
If you start with 4.5 moles of aluminum and 6.5 moles of copper chloride to make aluminum chloride and copper, what is the limit
Alex Ar [27]

Answer:

The limiting reagent is CuCl

Explanation:

The initial number of moles of aluminum, Al = 4.5 moles

The number of moles of copper, Cu = 6.5 moles

The given chemical reaction is presented as follows;

2Al + 3CuCl → 2AlCl₃ + 3Cu

Therefore, we have, 2 moles of aluminum combine with 3 moles of CuCl produces 2 moles of AlCl₃ and 3 moles of Cu

1 mole of Al will combine with (3/2) moles of CuCl,

Therefore, 4.5 moles of Al will combine with (4.5 × (3/2) = 6.75) 6.75 moles of CuCl

Given that the number of moles of CuCl present is only 6.5 moles which is less than the 6.75 moles required to combine with the 4.5 moles, the 6.5 moles of CuCl limits the amount of AlCl₃ and Cu produced, and therefore the CuCl is the limiting reagent.

8 0
3 years ago
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