Answer:
The limiting reagent is CuCl
Explanation:
The initial number of moles of aluminum, Al = 4.5 moles
The number of moles of copper, Cu = 6.5 moles
The given chemical reaction is presented as follows;
2Al + 3CuCl → 2AlCl₃ + 3Cu
Therefore, we have, 2 moles of aluminum combine with 3 moles of CuCl produces 2 moles of AlCl₃ and 3 moles of Cu
1 mole of Al will combine with (3/2) moles of CuCl,
Therefore, 4.5 moles of Al will combine with (4.5 × (3/2) = 6.75) 6.75 moles of CuCl
Given that the number of moles of CuCl present is only 6.5 moles which is less than the 6.75 moles required to combine with the 4.5 moles, the 6.5 moles of CuCl limits the amount of AlCl₃ and Cu produced, and therefore the CuCl is the limiting reagent.
