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3 years ago

Please help me solve this:

2 answers:

6 0

X+0.5 could be an inequality to represent the possible weight of the second fish, unless you can tell me the weight of the first fish?

Aliun [14]3 years ago

6 0

Answer:

The weight of second fish

$w\leq0.5+x$ pound.

Step-by-step explanation:

Given You catch two fishes

Let weight of I fish = x pound

If the weight of II fish atleast 0.5 pound more than the weight of I fish

The weight of II fish=w pound

Therefore, $w\leq x+0.5$

Where x= Weight of I fish

w= Weight of II fish

$\leq$ = Less than or equal to

"+" = Sign of addition

Because the weight of II fish is greater than the weight of I fish

The required expression for the weight of II fish

$w\leq x+0.5$ pound.

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which expression represents the sum of 2/3m - 1 1/6 and 5/6 - 1 1/3?a. 1 1/2m + 2 1/2b.1/6m - 1/3c.1 1/2m - 2 1/2d.1/6m + 1/3

damaskus [11]

I thinks its A. sorry if its wrong

8 0

3 years ago

Read 2 more answers

A player kicks a soccer ball from a height of 2 feet. The ball reaches A maximum height of 20 feet after traveling 40 feet horiz

Artyom0805 [142]

The height is 9.875 feet from which the goalkeeper catches the ball.

The player kicks soccer from a height of 2 feet

x = 0 and y = 2

Maximum height of 20 feet after traveling 40 feet

x = 40, y = 20

So let y = a(x - 40)² + 20 ( the path of parabola)

Since x = 0 , y = 2

So, 2 = a(0 - 40)² + 20

2 = 1600a + 20

-18 = 1600a

a = - 9/800

Thus, y = -9/800(x - 40)² + 20

Since the soccer is caught by the goalkeeper 70 feet from where it was kicked

x = 70

So at this time,

y = -9/800 ( 70 - 40)² + 20

= -9/800 × 900 + 20

= - 81/8 + 20

= 79/ 8

= 9.875 feet

Therefore the height at which the goalkeeper catches the ball is 9.875 feet.

To know more about the height refer to the link given below:

brainly.com/question/27030273

#SPJ1

7 0

1 year ago

A business assistant must leave more than $50 in the supply account. There is $200 in the account. The assistant needs to order

ELEN [110]

The correct answer is B, 14 boxes of pens

8 0

3 years ago

Read 2 more answers

A bookstore had 45 copies of a magazine. Yesterday, it sold 2/3 of them. Today, it sold 1/3 of what remained. How many copies do

Ket [755]

After the first day, 1/3 of the original amount remained:

... (1/3)·45 = 15

After the second day, 2/3 of that amount remained:

... (2/3)·15 = 10

The bookstore has 10 copies left.

6 0

3 years ago

The weights of steers in a herd are distributed normally. The variance is 10,000 and the mean steer weight is 1400lbs. Find the

saw5 [17]

Answer:

$P(1539$

And we can find this probability using the normal standard table with this difference:

$P(1.39$

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(1539,1580)$

Where $\mu=1400$ and $\sigma=\sqrt{10000}= 100$

We are interested on this probability

$P(1539$

And we can solve the problem using the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

Using this formula we got:

$P(1539$

And we can find this probability using the normal standard table with this difference:

$P(1.39$

5 0

3 years ago