The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10
So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)
Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z
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Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later.
So let's call it A. Let A = 25
Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later
Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later
Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727
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In summary, we found
A = 25
B = 21
C = 39
D = 22.2727
The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)
Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)
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Final Answer: 39
Answer:
Step-by-step explanation:
The key here is knowing that the equation of the line that passes through these points is same
Thus having (6,14) and (0,0), the slope is as follows;
m = y2-y1/x2-x1 = 0-14/0-6 = -14/-6 = 7/3
Now we can use this slope here to get the value of y in the question
All we need to do is tie write the equation of the line for between the points (6,14) and (2,y)
That would be;
7/3 = y-14/1-6
7/3 = y-14/-5
cross multiply;
-35 = 3(y-14)
-35 = -3y + 42
-3y = -35-42
-3y= -77
y = -77/3
y = 77/3
Simplify the following:
(k^3 k^7)/3 - 5
Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
k^(7 + 3)/3 - 5
7 + 3 = 10:
k^10/3 - 5
Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
k^10/3 - 15/3
k^10/3 - 15/3 = (k^10 - 15)/3:
Answer: (k^10 - 15)/3
Answer:
1- 4x -7 =29, x= 9
2-x/3 - 8 = 12, x=60
Step-by-step explanation:
4x-7 =29
4x= 29 +7
4x= 36
x= 9
x/3 -8 =12
x/3 = 12+ 8
x/3 = 20
x= 20(3)
x= 60
Slope = y2-y1 / x2 - x1
= -8-2 / -10-5
= -10 / -15
= 2/3
A