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3 years ago

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Mabel is comparing the prices of two car rental companies. Company A charges $35 per day and an additional $15 as service charge

s. Company B charges $42 per day and an additional $10 as service charges.
Part A: Write an equation to represent each company's total charges for renting a car for a certain number of days. For both equations (one for Company A and one for Company B), define the variable used. (4 points)

Part B: Which company would charge less for renting a car for 6 days? Justify your answer. (3 points)

Part C: How much money is saved by using the services of Company A instead of Company B to rent a car for 10 days? (3 points)

pleaseee i will give everybody brainliest pleasseeee

1 answer:

olga_2 [115]3 years ago

7 0

The answer to the question

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Part 1) $2x^{2}-32=0----> (-4,4)$

Part 2) $4x^{2}-100=0----> (-5,5)$

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see the attached figure

Step-by-step explanation:

Solve each quadratic equation

Part 1) we have

$2x^{2}-32=0$

Adds 32 both sides

$2x^{2}=32$

Divide by 2 both sides

$x^{2}=16$

take square root both sides

$x=\pm4$

therefore

The solutions are (-4,4)

Part 2) we have

$4x^{2}-100=0$

Adds 100 both sides

$4x^{2}=100$

Divide by 4 both sides

$x^{2}=25$

take square root both sides

$x=\pm5$

therefore

The solutions are (-5,5)

Part 3) we have

$x^{2}-55=9$

Adds 55 both sides

$x^{2}=9+55$

$x^{2}=64$

take square root both sides

$x=\pm8$

therefore

The solutions are (-8,8)

Part 4) we have

$x^{2}-140=-19$

Adds 140 both sides

$x^{2}=-19+140$

$x^{2}=121$

take square root both sides

$x=\pm11$

therefore

The solutions are (-11,11)

Part 5) we have

$2x^{2}-18=0$

Adds 18 both sides

$2x^{2}=18$

Divide by 2 both sides

$x^{2}=9$

take square root both sides

$x=\pm3$

therefore

The solutions are (-3,3)

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