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pashok25 [27]
3 years ago
7

The square of a number plus three times the number is 70. find the numbers.

Mathematics
1 answer:
Harrizon [31]3 years ago
3 0

Answer:

Step-by-step explanation:

The equation for that is

x^2+3x=70

If we subtract over the 70, we have a quadratic that we can factor to solve for the values of x that will make that equation true.

x^2+3x-70=0

Now we need the factors of 70 that will either add or subtract to give us the linear term of 3. The factors of 70 that will work are 10 and 7. 10 times 7 is 70, and 10 - 7 = 3:

x^2+10x-7x-70=0 and now we will factor by grouping:

(x^2+10x)-(7x-70)=0 and factor out what's common:

x(x+10)-7(x+10)=0

The factor (x + 10) is common, so we will now factor that out:

(x+10)(x-7)=0

By the Zero Product Property, either x + 10 = 0 or x - 7 = 0, so x = -10 or 7

Those are the 2 numbers that will work.

(-10)^2+3(-10)=70 simplifies to

100 - 30 which does in fact equal 70. OR

(7)^2+3(7)=70 which simplifies to

49 + 21 which also equals 70.

So you're done!

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Can somebody please explain and answer this for me? I really don't get it.
Tcecarenko [31]

Answer:

Results can be (-\frac{1}{3} )^5

Step-by-step explanation:

-The solution for this question:

(-\frac{1}{3} )^5 is equal to  (-\frac{1}{3}) × (-\frac{1}{3}) × (-\frac{1}{3}) × (-\frac{1}{3}) × (-\frac{1}{3})

-The calculation for (-\frac{1}{3} )^5:

(-\frac{1}{3} )^5 = -\frac{1}{243}

3 0
3 years ago
Explain why the x-coordinates of the points where the graphs of the equations y = 2−x and y = 8x+4 intersect are the solutions o
Luda [366]
Part 1)
We have two lines:  y = 2-x   and   y = 8x+4
Given two simultaneous equations that are both required to be true.
the solution is the points where the lines cross
Which is where the two equations are equal
Thus the solution that works for both equations is when
2-x = 8x+4
because
where that is true is where the two lines will cross and that is the common point that satisfies both equations.

Part 2) Make tables to find the solution to 2−x = 8x+4. take the integer values of x between −3 and 3

see the attached table
The table shows that none of the integers from [-3,3] work because in no case does
<span>2-x = 8x+4
</span>
To find the solution we need to rearrange the equation to the form x=n
2-x =8x+4
8x+x=2-4
9x=-2
x=-2/9

 The only point that satisfies both equations is
where
 x = -2/9
Find y:
   y = 2-x  = 2 - (-2/9) = 2 + 2/9 = 20/9
Verify we get the same in the other equation
y = 8x+4   =  8(-2/9) + 4 = 20/9 
Thus the only actual solution, being the point where the lines cross,
 is the point (-2/9, 20/9)------> (-0.22,2.22)

Part 3) how can you solve the equation 2−x = 8x+4 graphically?
<span>The point on the graph where the lines cross is the solution to the system of equations
</span>
using a graph tool
see the attached figure

the solution is the point (-0.22,2.22)

4 0
3 years ago
Heron's Formula:
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Answer:

√s(s-a) (s-b) (s-c)

Step-by-step explanation:

123456

herons formula

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1 year ago
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Answer:

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