Y-12÷2
because it says 12 less than y we subtract y-12 but then it says divided by 2 so then it is reasonable to say y-12÷2
Hi there!
For a line to be PARALLEL, it must contain the same slope.
The given line has a slope of 4, so we can use the point-slope formula to solve:
y1 = y-coordinate of given point
x1 = x-coordinate of given point
m = slope
Plug in the values:
Simplify:
Theta has a reference angle of 30° and is in Quadrant I or II.
Sin(theta) = ½
Basic angle: 30
<h3>What is the reference angle?</h3>
The acute angle between the terminal arm/terminal side and the x-axis. The reference angle is always positive. In other words, the reference angle is an angle sandwiched between the terminal side and the x-axis.
Angles: 30,
180-30 = 150
Because sin is positive in quadrants 1 and 2.
To learn more about the terminal side visit:
brainly.com/question/1982296
#SPJ1
Answer:
19
Step-by-step explanation:
1st you will use a^2+b^2=c^2
next you plug them in so it would be a^2+16^2=25^2
next you would solve it to a^2+256=625
then you would get 369 and square root it
and your answer will be 19.2.
So legnth is 7 more than 6 times width
l=7+6w
area=10 cm^2
lw=area
subsitute
7+6w for l
(7+6w)(w)=10
7w+6w^2=10
subtract 10 from both sides
6w^2+7w-10=0
factor
multiply 6 and -10
get -60
now find what 2 numbers multiply to get -60 and add to get 7
the answe ris -5 and 12
split up 7w into that
6w^2+7w-10=0
6w^2+12w-5w-10=0
group
(6w^2+12w)+(-5w-10)=0
undistribute factors
(6w)(w+2)+(-5)(w+2)=0
reverse distribute (ab+ac=a(b+c)
(w+2)((6w)+(-5))=0
(w+2)(6w-5)=0
set each to zero
w+2=0
subtract 2
w=-2
false, legnths cannot be negative
6w-5=0
add 5
6w=5
divide both sides by 6
w=5/6
subsitute
l=7+6w
l=7+6(5/6)
l=7+5
l=12
legnth=12 cm
width=5/6 cm
