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marta [7]
2 years ago
9

Find the value of :​

Mathematics
1 answer:
beks73 [17]2 years ago
7 0

Answer:

i) 66

ii) 536

Step-by-step explanation:

Check attachement(s) for solution.

  • Attachment - 1: Solution (i)
  • Attachment - 2: Solution (ii)

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Please help me with my math homework! show work please
pychu [463]
Pythagorean theorem:

AC² + BC² = AB²

since this is isosceles (2 sides the same length), we can just let BC = AC and get

AC² + AC² = AB²
2AC² = AB²
AC² = AB²/2
AC = √(AB² / 2)

\mathrm{AC} = \sqrt{ \left( 6 \sqrt{2} \right)^2 /2} \\ = \sqrt{72/2} = 6

AC and BC are 6 meters
6 0
4 years ago
I need help.........................
Harman [31]

Answer:

B (-17,7)

Step-by-step explanation:

A point reflected over the Y-Axis just changes the x sign. So (17,7) changes to (-17,7). The 17 to -17. The y stays as a 7.

Hope this helps.

5 0
3 years ago
I need the answer ? how can I solve the problem ?
Ilya [14]

Answer:

use the standard equation of parabola.

3 0
3 years ago
3 ? 7 ? 12 ? 2 = 514
Bess [88]
3 x 7 x 12 x 2 I think
4 0
2 years ago
Read 2 more answers
The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.
bearhunter [10]

Answer:

Kindly check explanation

Step-by-step explanation:

H0 : μ = 5500

H1 : μ > 5500

The test statistic assume normal distribution :

Test statistic :

(Xbar - μ) ÷ s/sqrt(n)

(5625.1 - 5500) ÷ 226.1/sqrt(15) = 2.1429 = 2.143

Pvalue from test statistic :

The Pvalue obtained using the calculator at df = 15 - 1 = 14 is 0.025083

α = 0.05

Since ;

Pvalue < α

0.025083 < 0.05 ; Reject H0

The confidence interval :

Xbar ± Tcritical * s/sqrt(n)

Tcritical at 95% = 1.761 ;

margin of error = 1.761 * 226.1/sqrt(15) = 102.805

Lower boundary : (5625.1 - 102.805) = 5522.295

(5522.295 ; ∞)

The hypothesized mean does not occur within the constructed confidence boundary. HENCE, there is significant eveidbce to support the claim that the true mean life of a biomedical device is greater than 5500

4 0
3 years ago
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