Solve for x and round to the nearest tenth for both (please:) )
1 answer:
Answer:
see explanation
Step-by-step explanation:
using the sine ratio in the right triangle.
sin23° = =
( multiply both sides by 7 )
7 × sin23° = x , then
x ≈ 2.7 ( to the nearest tenth )
----------------------------------------------------
using the tangent ratio in the right triangle
tan x = =
, then
x = (
) ≈ 57.8° ( to the nearest tenth )
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Answer:
Side of the square paper = 21 inches
Step-by-step explanation:
Let the square paper is having measure of each side = a inches
Esther cut this square piece into two pieces.
Let the other side of one rectangle piece = x inches
Perimeter of this piece = 2(a + x) inches
Similarly dimensions of the other rectangular piece will be = a inches × (a - x) inches
Perimeter of this piece = 2[a + (a - x)]
Since both the rectangular pieces have the same perimeter = 63
So, 2(a + x) = 2[a + (a - x)] = 63
2(a + x) = 2(2x - x)
a + x = 2a - x
2a - a = 2x
a = 2x
x =
Therefore, Perimeter = 2(a + x) = 2(a + ) = 63
= 63
3a = 63
a = 21
Therefore, measure of the sides of the square is 21 inches.
