Question

Solve for x and round to the nearest tenth for both (please:) )

Answer 1

Answer:

see explanation

Step-by-step explanation:

using the sine ratio in the right triangle.

sin23° = $\frac{opposite}{hypotenuse}$ = $\frac{x}{7}$ ( multiply both sides by 7 )

7 × sin23° = x , then

x ≈ 2.7 ( to the nearest tenth )

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using the tangent ratio in the right triangle

tan x = $\frac{opposite}{adjacent}$ = $\frac{27}{17}$ , then

x = $tan^{-1}$ ( $\frac{27}{17}$ ) ≈ 57.8° ( to the nearest tenth )