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Ann [662]
2 years ago
14

Solve for x and round to the nearest tenth for both (please:) )

Mathematics
1 answer:
Dmitrij [34]2 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

using the sine ratio in the right triangle.

sin23° = \frac{opposite}{hypotenuse} = \frac{x}{7} ( multiply both sides by 7 )

7 × sin23° = x , then

x ≈ 2.7 ( to the nearest tenth )

----------------------------------------------------

using the tangent ratio in the right triangle

tan x = \frac{opposite}{adjacent} = \frac{27}{17} , then

x = tan^{-1} ( \frac{27}{17} ) ≈ 57.8° ( to the nearest tenth )

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