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viktelen [127]
2 years ago
12

What point is marked on the number line?

Mathematics
2 answers:
dolphi86 [110]2 years ago
8 0
The answer would be -7/8. Hope this helps!
ivanzaharov [21]2 years ago
4 0

Answer:

The answer would be -7/8. Hope this helps!

Step-by-step explanation:

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Rewrite each expression without parentheses
USPshnik [31]

Answer:

once simplified the expression is, -6xy^4

(the ^ means an exponent)

7 0
3 years ago
What is the other angel? help
olga55 [171]

Answer:

59.7 degrees

Step-by-step explanation:

see attached

3 0
3 years ago
Please solve the problem ​
jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==>   <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==>   <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}

Similarly, you would find

Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}

You can solve the second system in the same fashion. You would end up with

P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}

3 0
3 years ago
Please solve: x^2+4x-8=0
Bezzdna [24]
x^2+4x-8=0\\\\\underbrace{x^2+2x\times2+2^2}_{use:(a+b)^2=a^2+2ab+b^2}-2^2-8=0\\\\(x+2)^2-4-8=0\\\\(x+2)^2-12=0\\\\(x+2)^2=12\iff x+2=\sqrt{12}\ or\ x+2=-\sqrt{12}\\\\x=\sqrt{4\times3}-2\ or\ x=-\sqrt{4\times3}-2\\\\x=\sqrt4\times\sqrt3-2\ or\ x=-\sqrt4\times\sqrt3-2\\\\\center\boxed{x=2\sqrt3-2\ or\ x=-2\sqrt3-2}
4 0
3 years ago
Read 2 more answers
What is 1/8 as a whole number?
Degger [83]
Could it be like 1/8 of 100?
3 0
3 years ago
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