Step-by-step explanation:
11/12-?=2/3
11/12-2/3=?
11-8/12=?
3/12
=1/4
which one ?
the bottom or the top or is this a trick
Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.
Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.
Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.
The total number of ways the study can be selected is: 637065
Given,
Total number of women in a group= 13
Total number of men in a group = 12
Number of women chosen = 8
Number of men chosen = 8
∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.
This in the form of combination factor = nCr
∴ nCr = n!/(n₋r)! r!
13C₈ = 13!/(13 ₋ 8)! 8!
= 13!/5!.8!
= 1287
12C₈ = 12!/(12₋8)! 8!
= 12!/5! 8!
= 495
Now multiply both the combinations of men and women
= 1287 × 495
= 637065
Hence the total number of ways the study group is selected is 637065
Learn more about "Permutations and Combinations" here-
brainly.com/question/11732255
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Answer:
It is A
Step-by-step explanation:
The guy below is wrong because I got a 100 on the quiz on Edge.
