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IrinaVladis [17]
3 years ago
15

What is 0.422 rounded to the nearest thousandth

Mathematics
1 answer:
Maru [420]3 years ago
8 0
.4 is tenths .42 is hundredths and .422 is thousandths
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A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?​
zzz [600]

Answer:

\boxed{ \bold{ \huge{ \boxed{  \sf 240 \:  {inches}^{2} }}}}

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

Area of a rectangle = ?

Let width of a rectangle be ' w ' .

<u>Fi</u><u>rst</u><u>,</u><u> </u><u>finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u>

\boxed{ \sf{perimeter = 2(l + w)}}

plug the values

⇒\sf{64 = 2(20 + w)}

Distribute 2 through the parentheses

⇒\sf{64 = 40 + 2w}

Swap the sides of the equation

⇒\sf{40 + 2w = 64}

Move 2w to right hand side and change it's sign

⇒\sf{2w = 64 - 40}

Subtract 40 from 64

⇒\sf{2w = 24}

Divide both sides of the equation by 2

⇒\sf{ \frac{2w}{2}  =  \frac{24}{2} }

Calculate

⇒\sf{w = 12 \: inches}

Width of a rectangle ( w ) = 12 inches

<u>Now</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>having</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>2</u><u>0</u><u> </u><u>inches</u><u> </u><u>and </u><u>width </u><u>of</u><u> </u><u>1</u><u>2</u><u> </u><u>inches</u>

\boxed{ \sf{area \: of \: rectangle = length \:  \times  \: \: width}}

plug the values

⇒\sf{area \: of \: rectangle =20 \times  12 }

Multiply the numbers : 20 and 12

⇒\sf{area \: of \: rectangle = 240 \:  {inches}^{2} }

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

7 0
3 years ago
Werner's Deli can make 2.2 sandwiches
netineya [11]

Answer:

Hi there!

Your answer is:

66 sandwiches

Step-by-step explanation:

2.2sandwhiches per 1 min

× 30

66 sandwiches per 30 minutes!

Hopefully this helps

7 0
3 years ago
G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =
laiz [17]

Given:

The two functions are:

g(b)=5b-9

h(b)=(b-1)^2

To find:

The value of (h\circ g)(-6).

Solution:

We have,

g(b)=5b-9

h(b)=(b-1)^2

We know that,

(h\circ g)(b)=h(g(b))

(h\circ g)(b)=h(5b-9)

(h\circ g)(b)=[(5b-9)-1]^2

(h\circ g)(b)=[5b-10]^2

Putting b=-6, we get

(h\circ g)(-6)=[5(-6)-10]^2

(h\circ g)(-6)=[-39-10]^2

(h\circ g)(-6)=[-49]^2

(h\circ g)(-6)=2401

Therefore, the value of (h\circ g)(-6) is 2401.

7 0
3 years ago
IGNOR MY ANSWER I ALSO NEED TO KNOW IF IT'S OPEND OR CLOSED Graph the solution to this inequality on the number line.
Alex777 [14]

Answer:

open circle

Step-by-step explanation:

\leq \geq = closed cirle\\ =open circle

6 0
2 years ago
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Svetllana [295]

Step-by-step explanation:

2.5<x<8.0???????????

3 0
3 years ago
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