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Deffense [45]
2 years ago
7

Can i have some help i spent a lot of points and it didn't work :((((

Mathematics
1 answer:
Ivahew [28]2 years ago
5 0

Answers for A:

Factored form: (x-2)(x+4)

Zeros: x = 2, -4

Vertex: (-1, -9)

Answers for B:

Factored form: -(x+2)(x+7)

Zeros: x = -2, -7

Vertex: (-9/2, 25/4)

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A packet of garden seeds contains 250 seeds. The information printed on the packet indicates that the germination rate for this
Westkost [7]

Answer:

Expectation=240

standard deviation=3.098

Step-by-step explanation:

This is a binomial probability function with n=250 and probability of success is 96%

-The expected value is calculated as:

E(X)=np\\\\=250\times 0.96\\\\=240

Hence, the expected germination is 240 seeds

b. From a above, we have the value of p=0.96 and n=250.

The standard deviation of germination is therefore calculated using the formula:

\sigma=\sqrt{np(1-p)}, \ \ \ \\\\=\sqrt{250\times 0.96(1-0.96)}\\\\\\=3.098

Hence, the standard deviation of germination is 3.098

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3 years ago
Which type of graph would allow us to quickly see how many months between 100 and 200 students were treated?
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The type of graph that would allow us to quickly see how many students were treated would be a Bar graph.

7 0
3 years ago
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Use the diagram to help you solve the problem.
Harrizon [31]

Answer:

C

Step-by-step explanation:

Just took it

4 0
3 years ago
The length of a rectangle is 2 more than twice the width. The area of the
vlada-n [284]

Answer: w=5 , L= 2+2(5)=12

Step-by-step explanation:

L=2+2W

A= 60

LxW=60, now we will replace the L

(2+2W)(W)=60   we multiply

2w^2+2w=60

2w^2+2w-60=0  we divide by 2 the equation so we can work easier

w^2+w-30=0

find out w using the quadratic equation

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3 years ago
A Food Marketing Institute found that 39% of households spend more than $125 a week on groceries. Assume the population proporti
Anuta_ua [19.1K]

Answer:

0.6210

Step-by-step explanation:

Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries

Sample size n =87

Sample proportion will follow a normal distribution with p =0.39

and standard error = \sqrt{\frac{0.39(1-0.39)}{87} } \\=0.0523

the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41

=P(0.29

There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41

7 0
4 years ago
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