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2 years ago

What is the product of 9 radical 5 and 5 radical 10 in simplest radical form?

Mathematics

1 answer:

tatuchka [14]2 years ago

3 0

Answer:

Step-by-step explanation:

(9√5) (5√10)

The leading interger product is found by multiplying 9 and 5

The leading integer product is 9*5 = 45

The radical product is (√5*10

Factor 10

radical product = √5*2*5

There are 2 fives underneath the radical. Take one out and ignore the other

radical product = 5√2

The 5 now multiplies by 45 and √2 becomes part of the answer

5*45√2

225√2

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3 years ago

Suppose two dice are tossed and the numbers on the upper faces are observed. Let S denote the set of all possible pairs that can

lesya [120]

Answer:

The set A={(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,(2,6),(3,6),(4,6),(5,6),(6,6)}

B={(2,2),(4,2),(6,2),(2,4),(2,6),(1,3),(1,5),(1,1),(3,1),(3,3),(3,5),(4,4),(4,6),(5,1),(5,3),(5,5),(6,4),(6,6)}

C={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,3),(2,5),(3,3),(3,5),(3,4),(3,6),(4,1),(4,3),(4,5),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,3),(6,5)}.

A∩B:{(2,2),(4,2),(6,2),(2,4),(2,6),(4,4),(4,6),(6,4),(6,6)}

A∪B={(1,2),(2,2),(4,2),(6,2),(2,4),(2,6),(4,4),(4,6),(6,4),(6,6),(3,2),(5,2),(1,4),(3,4),(5,4),(1,6),(3,6),(5,6),(1,3),(1,5),(1,1)(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)}

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Step-by-step explanation:

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3 years ago

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