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Molodets [167]
2 years ago
5

What is the product of 9 radical 5 and 5 radical 10 in simplest radical form?

Mathematics
1 answer:
tatuchka [14]2 years ago
3 0

Answer:

Step-by-step explanation:

(9√5)   (5√10)

The leading interger product is found by multiplying 9 and 5

The leading integer product is 9*5 = 45

The radical product is (√5*10

Factor 10

radical product = √5*2*5

There are 2 fives underneath the radical. Take one out and ignore the other

radical product = 5√2

The 5 now multiplies by 45 and √2 becomes part of the answer

5*45√2

225√2

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Answer:

# A circumscribed angle is created by two intersecting tangent segments ⇒ true (1st answer)

# The measure of a central angle will be twice the measure of an inscribed angle that intercepts the same arc ⇒ true (3rd answer)

# The measure of a central angle will be equal to the measure of an inscribed angle when the arc intercepted by the inscribed angle is twice as large as the arc intercepted by the central angle ⇒ true (6th answer)

Step-by-step explanation:

* Lets revise the types of angles in a circle

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- Ex:

∵ AB and AC are tangent to circle M at B and C

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Ex:

∵ XY and XZ are two chords in circle M

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- Ex:

∵ MA and MB are two radii of circle M

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- The measure of an inscribed angle is half the measure of the

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- Ex:

∵ ∠ABC is an inscribed angle in circle M subtended by arc AC

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* Lets solve the problem

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# A circumscribed angle is created by two intersecting tangent

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∵ XYZ is an inscribed angle of circle M subtended by arc XZ

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