What is the product of 9 radical 5 and 5 radical 10 in simplest radical form?

Mathematics

1 answer:

tatuchka [14]2 years ago

3 0

Answer:

Step-by-step explanation:

(9√5) (5√10)

The leading interger product is found by multiplying 9 and 5

The leading integer product is 9*5 = 45

The radical product is (√5*10

Factor 10

radical product = √5*2*5

There are 2 fives underneath the radical. Take one out and ignore the other

radical product = 5√2

The 5 now multiplies by 45 and √2 becomes part of the answer

5*45√2

225√2

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