Answer:
Step-by-step explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
The population proportion have the following distribution
And we can solve the problem using the z score on this case given by:
We are interested on this probability:
And we can use the z score formula, and we got this:
And we can find this probability like this:
Step-by-step explanation:
c >= 2
that means any value of c greater or equal to 2 is a valid solution. so, yes, 2 is a solution for this.
c < 2
that means any value of c smaller than 2 is a valid solution. so, no, 2 is not smaller than 2, so it is not a solution.
c < 3
that means any value of c smaller than 3 is a valid solution. so, yes, 2 is smaller than 3, so 2 is a solution.
3 < c
that means any value of c, for that 3 is smaller, is a valid solution. our in other words, any value for c larger than 3 is a valid solution. so, no, 2 is not larger than 3, so it is not a solution.
-8 < c
that means any value of c, for that -8 is smaller, is a valid solution. our in other words, any value for c larger than -8 is a valid solution. so, yes, 2 is larger than -8, so it is a solution.
Answer:
-46
Step-by-step explanation:
We need to find the common difference of this arithmetic sequence:
So, the common difference d = -4. We can now write the equation:
So, the 15th term is -46.
Hope this helps!
It would be 100,300
Hope this helped
In this attached picture, we can prove that triangles AOB and COD are congruent. ∠CDO and ∠ABO are equal because they are alternate angles. Similarly, ∠OAB and ∠OCD are equal because they are alternate angles, as well. We have a rectangle and in the rectangle, opposite sides are equal; AB = CD. Then, because of Angle-SIde-Angle principle, we can say that triangles AOB and COD are equal. If triangles are congruent, then OD = OB and OC = AO. Applying congruency to the triangles ACD and BCD, we can see that these triangles are also congruent. It means that the diagonals are equal. Since, OD = OB and OC = AO, it proves that the point O simultaneously is the midpoint and intersection point for the diagonals.
