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rusak2 [61]
3 years ago
15

if 6th term of an ap is -10 and 10 th term is -26 then find thr 15 term​ plzzzzzzzzzzzzzzzzzzzzzzz answer i will give whatever y

ou want

Mathematics
2 answers:
Rudik [331]3 years ago
5 0

Answer:

-46

Step-by-step explanation:

We need to find the common difference of this arithmetic sequence:

\frac{-26-(-10)}{10-6} =\frac{-16}{4} =-4

So, the common difference d = -4. We can now write the equation:

a_n=a_1+d(n-1)

a_{15}=a_6+d(15-6)=-10-4(9)=-10-36=-46

So, the 15th term is -46.

Hope this helps!

Anna007 [38]3 years ago
4 0

Step-by-step explanation:

the answer and explanation is in the picture

please rate and mark as brainliest

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2 years ago
Solve the equation using the method of completing the square.
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Answer:

D) x = ± 2√5 - 4

Step-by-step explanation:

2x² + 16x - 8 = 0

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2 years ago
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VARVARA [1.3K]
I think it’s b

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8 0
3 years ago
Pam’s grandfather has a garden that measures 4 feet by 6 feet. How much will the area be increased if he doubles the length and
ExtremeBDS [4]

Answer:

The area will be increased by 72 feet.

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4 x 6 = 24

Now we have to double those lengths.

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7 0
2 years ago
After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos
igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P  and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

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d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}

and we found the distance PQ and QA

; d_{PQ}=\sqrt{125}, d_{QA}=12

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0
3 years ago
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