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Sav [38]
3 years ago
10

¿Cuál es el doble de un número menos nueve?

Mathematics
1 answer:
zalisa [80]3 years ago
7 0

Answer:

2x menos nueve

Step-by-step explanation:

por dos x menos nueve

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Given 2x² = -8, x is<br> A) -2 <br> B) 2<br> C) 2i or -2i <br> B) 4i or -4i<br> NO LINKS!!!
faust18 [17]

Answer:

2x^2=-8

2x^2/2=-8/2

x^2=-4

x=2

Step-by-step explanation:

HOPE THAT THIS IS HELPFUL.

HAVE AN AWESOME DAY.

4 0
2 years ago
Solve for -2&lt;-3-3x&lt;0
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How to do this problem
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3 years ago
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Step-by-step explanation:

6 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
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