All categories

1 year ago

Find the missing side of the right triangle. Leave answer in

Mathematics

1 answer:

Olenka [21]1 year ago

8 0

It is d. you can solve the question with Pythagorean

You might be interested in

2. XYZW is a parallelogram with diagonals XZ and YW that intersect at point A.

sergeinik [125]

Answer:

AW=10

Step-by-step explanation:

In a parallelogram opposite sides are congruent meaning XA and AZ are congruent. YA and AW are congruent. So...

Solving for XA and AZ

XA=AZ

3m=5m-4

-2m=-4

m=2

If YW=10m then 10 x 2 = 20

20 divided by 2 = 10

4 0

2 years ago

−5 1 3 − 2 1/3 zzzzzzzzzzzzzzz

Leona [35]

Answer:

5 1/3

Step-by-step explanation:

6 0

1 year ago

Read 2 more answers

Show the work for answer, if the area of a pizza is 153.94 square inches, find the length of its diameter

TEA [102]

Answer:

14 inch

Step-by-step explanation:

A = πr^2

153.94 = π * r^2

153.94/π = 49.001 = r^2

√49.001 = r = 7

radius * 2 = diameter

7 * 2 = 14 inch diameter

7 0

2 years ago

NEED HELP i dont know how to do this and i need to turn in soon

bulgar [2K]

Answer:

f(-1) = 0 and f(4) = 0

Step-by-step explanation:

look at graph to see what point(s) is/are intersecting the y-axis, then use the y-value of the ordered pair

8 0

2 years ago

A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng

tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, $xy \leq 8000$

So, $x(220-x) \leq 8000$

$220x-x^2 \leq 8000$

So, $220x-x^2 = 8000\\-x^2+220x-8000=0$

General quadratic equation : $ax^2+bx+c=0$

Formula : $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031$

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0

2 years ago