x = 109
this is pentagon
the sum of the interior angles of a polygon is
sum = 180°( n - 2) where n is the number of sides.
sum = 180° × 3 = 540° thus
x + 121+ 108 + 102 + 100 = 540
x + 431 = 540
subtract 431 from both sides
x = 540 - 431 = 109
Let
x--------> the length side of the square base
h--------> the height of the box
we know that
<u>the volume of the box is equal to</u>
so
<u>the surface area of the box is equal to</u>
(remember that the box is open)
area of the base=
Perimeter of the base=
height=(h) m
substitute
we know that
the value of x can not be negative and the denominator can not be zero
therefore
<u>the answer is</u>
the domain of SA is x> 0
the domain is the interval-------------> (0,∞)
Answer: 14.8
Explanation: You’re trying to find the hypotenuse using the two legs that you have. The formula to find hypotenuse is a^2+b^2=c^2. You are trying to find c^2. So it would be 10^2+11^2=c^2. 10^2 is 100 and 11^2 is 121 and 100+121 is 221. Then you would square root 221 and get 14.8 for the hypotenuse.
Answer:
Get the equation in the form y = ax2 + bx + c.
Calculate -b / 2a. This is the x-coordinate of the vertex.
To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y.
Step-by-step explanation:
