Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is 
is correct answer
Therefore ![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2%3D%5Cfrac%7B1%7D%7B3%5E8%7D)
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
( using the property 
)
( using the property 
( combining the like powers )
( using the property 
)
( using the property 
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is is correct answer
Answer:
7
Step-by-step explanation:
When you match the form
... ax² + bx + c = 0
to the equation
... 3x² + 5x + 7 = 0
it is reasonable to conclude that ...
... a = 3, b = 5, c = 7.
_____
The question presumes you are familiar with the form
... ax² +bx +c = 0
which is often used as the representation of a general quadratic equation. This lets us use a, b, and c instead of specific numbers, to talk about ways of factoring, graphing, or solving equations like this.
Answer:
-45
Step-by-step explanation:
When the -4 is plugged in, it needs to be multiplied and then added to 39. That equals -45.
She posted 2/5 of them
90 times 2/5=180/5=36
she posted 36
90-36=54
she posted 2/3 of remaining (54)
2/3 times 54=108/3=36
54-36=18
she has not yet posted 18 of them
Answer:
I think it would be -4x-6y+12
