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Marizza181 [45]
3 years ago
6

At beginnings of population study a city had 330,000 people. Eac year since, the population has grown by 6.8% . let t be the num

ber of years since of study. let y be the cory population write an exponential function showing the relationship between y and t.​
Mathematics
1 answer:
insens350 [35]3 years ago
3 0

Answer:

Y=330,000(1.068)^t

Step-by-step explanation:

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What is the domain of the function shown in the graph below?
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Answer: interval from -8 to 5

In interval notation, we would write [-8, 5]

The domain is the set of allowed x inputs to a function. The left-most point is (-8,0) so x = -8 is the smallest x value allowed. The largest x value allowed is x = 5 due to the point (5,0) being the right-most point.

The use of square brackets in interval notation says "include this endpoint as part of the interval".

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Are the triangles similar? If so, what postulate or theorem proves their similarity?
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SAS, two given sides are 40% longer, one angle is shared

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Review the graph of complex number z.<br> What is the modulus of<br> Z.
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Step-by-step explanation:

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En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que
Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0
3 years ago
Using the equation 4x^3-6x^2-144x+8, find the function values f(-3) and f(-4) at the interval {-4,5}
Leto [7]

Answer: f(-3) = 278, f(-4) = 232

Step-by-step explanation:

f(x) = 4x³ - 6x² - 144x + 8

f(-3) = 4(-3)³ - 6(-3)² - 144(-3) + 8

f(-3) = 4(-27) - 6(9) - 144(-3) + 8

f(-3) = 278

f(-4) = 4(-4)³ - 6(-4)² - 144(-4) + 8

f(-4) = 4(-64) - 6(16) - 144(-4) + 8

f(-4) = 232

7 0
3 years ago
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