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qwelly [4]
3 years ago
10

Find the value of the expression

Mathematics
1 answer:
astraxan [27]3 years ago
7 0

Answer:

19

Step-by-step explanation:

5*7 - 4*4

PEMDAS says multiply and divide first

35 - 16

Then add and subtract

19

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Given that θ terminates in Quadrant III and tanθ 5/12= , find cscθ
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\bf tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
csc(\theta)=\cfrac{hypotenuse}{opposite}
\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{5}{12}\cfrac{\leftarrow opposite=b}{\leftarrow adjacent=a}\\\\
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\textit{let's use the pythagorean theorem to get the hypotenuse "c"}
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c^2=a^2+b^2\implies c=\pm\sqrt{a^2+b^2}\implies c=\pm\sqrt{12^2+5^2}
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\boxed{c=\pm 13}

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now, that we know what the hypotenuse "c" is, well
 
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