Answer:
i think the answer is (B)
Step-by-step explanation:
The y value of a point where a vertical line intersects a graph represents an output for that input x value. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output.
1) 20x+5y=120
Stp1: 5y=120-20x
Stp2: 5y=(120/5 and -20x/5)= [y=24-4x]
finding x:
20x+5(24-4x)=120
Stp1: 5*24=120,-4x*5=-20
20x+120-20x=120
Stp2: subtract 120 on both sides of = sign
20x-20x=0
Stp3: subtract the variables:
[x=0]
finding y:
20(0)+5y=120
stp1: multiply 20*0
5y=120
stp2: divide 120 by 5
[y=24]
2) 10x+7.5y=80
Stp1: move 7.5y to other sign of =
10x=80-7.5y
Stp2: divide by 10
[x=8-.75y]
substitute x and re do original:
stp1: 10(8-.75y)+7.5y=80
stp2: 80-7.5y+7.5y=80
stp3: subtract variabled num. with variabled num. and whole num. with whole number: [y=0]
solve for x:
10x-7.5(0)=80
10x=80
[x=8]
check:
10(8)+7.5(0)=80
80+0=80
[80=80]
Answer:
41< (or equal to) x < (or equal to) 45
Step-by-step explanation:
Answer:
First odd number = 13
Second odd number = 15
Step-by-step explanation:
Let
First odd number = 2x + 1
Second odd number = 2x + 3
According to given conditions:
32 + 2x + 1= 3 (2x + 3)
33 + 2x = 6x + 9
Taking terms with x to left and constants to right
2x - 6x = 9 - 33 (sign of transferred terms will be changed)
-4x = -24
Dividing both sides by -4
x = -24/-4
x =6
So,
First odd number = 2x + 1 = 2*6 + 1 = 12 + 1 =13
Second odd number = 2x + 3= 2*6 +3= 12 + 3 = 15
I hope it will help you!
Answer:
Step-by-step explanation:
12) The amount of the initial deposit is $1000
13) the slope is (y2 - y1)/(x2 - x1)
Slope = (4000 - 3000)/(6 - 4)
Slope = 1000/2 = 500
The y intercept is the value of y when x is zero. Therefore,
y intercept = 1000.
14) The equation of a straight line represented in the slope intercept form is
y = mx + c
Where
m represents slope
c represents intercept
Therefore the equation is
y = 500x + 1000
15) The slope represents rate of change in the amount saved with respect to time in months.
