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Dima020 [189]
4 years ago
9

Help pls fast as u can

Mathematics
1 answer:
weqwewe [10]4 years ago
6 0

The number 72 should replace the question mark.

Step-by-step explanation:

Step 1:

First, we need to determine how the values inside the triangles were attained in terms of the outer values.

We get that summing the bottom values on the triangle and multiplying it with the value on top equals the value in the triangle.

For triangle 1, (3+5)2 = (8)2 =16,

For triangle 2, (1+7)5 = (8)5 =40,

For triangle 3, (9+2)3 = (11)3 =33.

Step 2:

By using the same method for the fourth triangle we have;

For triangle 4: (3+6)8 = (9)8 =72.

So the question mark equals 72.

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A meatball recipe calls for 2 cups of breadcrumbs for every 5 cups of ground meat. How many cups of breadcrumbs are required for
Ghella [55]

Answer:

1/4 cup for every cup

Step-by-step explanation:

If you divide 2 by 5, you would get this answer. Sorry if it's wrong!

6 0
3 years ago
The product of a number and 3 increased by 9 is less than -42<br><br><br> TRANSLATE
nikitadnepr [17]

Answer:

3x+9 < - 42

Step-by-step explanation:

4 0
3 years ago
Phil has drawn some house plans in which the lounge room will be 9.5 m long when it is built. This length has been drawn as 19cm
Monica [59]

Answer:

1:50 scale

Step-by-step explanation:

9.5m * 100 = 950cm

950/19 = 50

7 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
tresset_1 [31]

Because I've gone ahead with trying to parameterize S directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over S straight away, let's close off the hemisphere with the disk D of radius 9 centered at the origin and coincident with the plane y=0. Then by the divergence theorem, since the region S\cup D is closed, we have

\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV

where R is the interior of S\cup D. \vec F has divergence

\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z

so the flux over the closed region is

\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0

\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}

Parameterize D by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k

with 0\le u\le9 and 0\le v\le2\pi. Take the normal vector to D to be

\vec s_u\times\vec s_v=-u\,\vec\jmath

Then the flux of \vec F across S is

\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0

\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}

8 0
3 years ago
What is the value of y?<br><br><br><br> Enter your answer in the box.
Elenna [48]
The value of y = 40.

5x = 40
  x = 8

180 = 40 + 40 + (2y + 20)
  40 = y
7 0
3 years ago
Read 2 more answers
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