2 years ago

Precalculus real mathematics real people 7th edition solutions

SAT

1 answer:

Varvara68 [4.7K]2 years ago

7 0

Figure it out yourself lol

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Can anyone solve this for me

ladessa [460]

(x+y)^2=56
x^2+2xy+y^2=56. we know that xy=12
so 2(xy)=24
x^2+24+y^2=56
x^2+y^2=56-24
x^2+y^2=32. <-------------

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3 years ago

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gtnhenbr [62]

Answer:

^^^^^^^^^^^^^^^^^^^

Explanation:

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3 years ago

Three hunters are walking side by side. Which of the following would be safe?

PtichkaEL [24]

Answer:

the hunter in the center uses the trial carry.

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3 years ago

Which of the following might be requested on a typical job application?

Neko [114]

Answer:

D. Graduation date

Explanation:

Some <em>job applications</em> ask for the date you graduated high school or college, although it tends to raise questions about <em>why the company would ask such a thing in the first place</em>.

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3 years ago

Soon Yi loves to bake, and she is making flaky pastry. Soon Yi starts with a layer of dough 222 millimeters (\text{mm})(mm)left

frozen [14]

Answer:

3 times

Explanation:

When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

$T(n)=T_0(1+r)^n$

Where:

Initial thickness, $T_0$ = 2mm

Growth factor, r =8%=0.08

We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.

i.e When $T(n)\geq 2.5$ mm$

$2(1+0.08)^n\geq 2.5\\2(1.08)^n\geq 2.5\\$Divide both sides by 2$\\\dfrac{2(1.08)^n}{2}\geq \dfrac{2.5}{2}\\\\1.08^n\geq 1.25\\\\$Change to logarithm form\\n \geq \log_{1.08}1.25\\\\n\geq \dfrac{\log 1.25}{\log 1.08} \\\\n\geq 2.9$

Therefore, the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm thick is 3.

4 0

4 years ago

Read 2 more answers