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3 years ago

13

The cost function of a game store is C=$5.50n+$700 and the revenue function is R=$9n. how many games does the store need to sell

to break even?

2 answers:

rewona [7]3 years ago

5 0

The answer would be 200

Tatiana [17]3 years ago

3 0

The answer would be 200 because you would solve the equation 5.50+700=9n. Once you do, you end up with 200. And if you plug it in it equals the same.

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What is 37% as a fraction and a decimal

White raven [17]

37% as a fraction is 37/100
37% as a decimal is 0.37

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While shopping for clothes, Daniel spent $34 less than 3 times what Jaclyn spent. Daniel spent $14. Write and solve an equation

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Answer: Jaclyn spent $48

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3x - 34 = 14

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3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

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1 year ago

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2 years ago

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Which of the following is equivalent to the inequality shown below?

VARVARA [1.3K]

Answer:

$4x + 0.9 \geq 0.1$ is equivalent to the inequality $40x+9 \geq 1$

Step-by-step explanation:

Given inequality : $4x + 0.9 \geq 0.1$

We are supposed to find Which of the following is equivalent to the inequality

$4x + 0.9 \geq 0.1$

$\Rightarrow 4x+\frac{9}{10} \geq \frac{1}{10}$

Multiply both sides by 10

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$4x + 0.9 \geq 0.1$ is equivalent to the inequality $40x+9 \geq 1$

So, Option B is true

B) $40x+9 \geq 1$

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