A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet,
and the angles of elevation are given. a. Find BC, the distance from Tower 2 to the plane, to the nearest foot.
b. Find CD, the height of the plane from the ground, to the nearest foot.
The question is asking to find and calculate the said towers base on the given in the question. In my own calculation, I would say that the answers are the following.A. the distance from tower 2 to the plane to the nearest foot is 15052.1 ftB. the height of the plane from the ground, to the nearest foot is 6122 ft.
Standard form: Ax+By=C first put in slope-intercept form: slope = (0+5)/(6-3) = 5/3 pick point D: 0 = 5/3(6)+b -> b= -10 slope-intercept form: y=(5/3)x-10 multiply both sides by 3: 3y=5x-30 put in standard form: 5x-3y=30
