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Reika [66]
3 years ago
9

Is it possible that all solutions of a homogeneous system of ten linear equations in twelve variables are multiples of one fixed

nonzero solution
Mathematics
1 answer:
sukhopar [10]3 years ago
7 0

The answer is no, because the Rank Theorem tells us that rank A + dim Nul A = 12 . Since the rank can be at most 10, the null space has to have dimension at least two.

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How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
chubhunter [2.5K]

Answer:

It's a direct variation condition,

hence ratio remains constant.

39 - 3

x - 4

x = 4×39/3 = 4×13 = 52 .. (for first blank space)

39 - 3

x - 10

x = 39×10/3 = 13×10 = 130 .. (for second blank space)

6 0
2 years ago
Read 2 more answers
How to solve this question
Katarina [22]
Direct variation can be written as a proportion. Therefore, we can write:

\frac{8}{4}= \frac{y}{5}
Cross multiply to get:
4y=40
Divide by 4 on both sides to get that y=10.

:)

3 0
3 years ago
A cleaner charges $0.50 per square foot to polish wood floors. a school hall has a floor area of 30 feet by 50 feet. what would
nexus9112 [7]
First calculate the area of the floor, this would be 30*50 = 1500 square feet
Now multiply the area by the cost for each square foot, so 1500*0.5 = $750
7 0
3 years ago
Read 2 more answers
2. y = -2x² + 8x<br>Axis of Symmetry:<br>Vertex:<br>Domain:<br>Range:​
worty [1.4K]

Answer:

Part 1) The axis of symmetry is x=2

Part 2) The vertex is the point (2,8)

Part 3) The domain is all real numbers

Part 4) The range is all real numbers less than or equal to 8

Step-by-step explanation:

we have

y=-2x^{2}+8x

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

step 1

Find the vertex

Convert the quadratic equation in vertex form

Factor -2 leading coefficient

y=-2(x^{2}-4x)

Complete the square

y=-2(x^{2}-4x+4)+8

rewrite as perfect squares

y=-2(x-2)^{2}+8

so

The vertex is the point (2,8)

step 2

Find the axis of Symmetry

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

the vertex is the point (2,8)

therefore

The axis of symmetry is x=2

step 3

Find the domain

The domain of the quadratic equation is the interval ------> (-∞,∞)

The domain is all real numbers

step 4

Find the range

The range of the quadratic equation is the interval ------> (-∞,8]

y\leq 8

The range is all real numbers less than or equal to 8

5 0
3 years ago
Find the value of x.
Jobisdone [24]
X=180-125-39=16 degrees
6 0
3 years ago
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