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2 years ago

How do i solve this?

Mathematics

1 answer:

slava [35]2 years ago

4 0

Answer:

Step-by-step explanation:

to solve for each triangle remember its 1/2 base times height you have four of those so add those four sides to the area of the square.

key concept: 1/2(Base*Height)

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Solve and graph on a number line -6x+5<-15.2

Kaylis [27]

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3 years ago

HELP!!! 30 pts!

bezimeni [28]

Answer:

(X+2)power of 2 + (y + 3)power of 2 = 9

Step-by-step explanation:

8 0

3 years ago

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There are currently 16 teams in the National Football Conference (NFC). Of those teams, 11 have won at least one super bowl and

svp [43]

You are given 16 teams, 11 have won at least one super bowl and 5 have not.

A. The probability that both selected teams have won at least 1 super bowl is

$Pr(A)=\dfrac{C_{11}^2}{C_{16}^2}=\dfrac{\dfrac{11!}{2!(11-2)!}}{\dfrac{16!}{2!(16-2)!}}=\dfrac{\dfrac{10\cdot 11}{2}}{\dfrac{15\cdot 16}{2}}=\dfrac{55}{120}=\dfrac{11}{24}.$

B. The probability that neither selected team has won at least 1 super bowl is

$Pr(B)=\dfrac{C_{5}^2}{C_{16}^2}=\dfrac{\dfrac{5!}{2!(5-2)!}}{\dfrac{16!}{2!(16-2)!}}=\dfrac{\dfrac{4\cdot 5}{2}}{\dfrac{15\cdot 16}{2}}=\dfrac{10}{120}=\dfrac{1}{12}.$

C. The probability that at least one selected team has won at least 1 super bowl is

$Pr(C)=1-Pr(B)=1-\dfrac{1}{12}=\dfrac{11}{12}.$

D. to find the probability that the second team selected has won at least 1 super bowl given that the first team selected has not won a super bowl, consider such events:

P - the second team selected has won at least 1 super bowl;

Q - the first team selected has not won a super bowl.

Then

$Pr(P|Q)=\dfrac{Pr(P\cap Q)}{Pr(Q)}=\dfrac{\dfrac{5\cdot 11}{C_{16}^2}}{\dfrac{C_5^1\cdot C_{15}^1}{C_{16}^2}}=\dfrac{55}{75}=\dfrac{11}{15}.$

E. To find the probability that the second team selected has won at least 1 super bowl given that the first team selected has won at least 1 super bowl, consider events:

M - the second team selected has won at least 1 super bowl;

N - the first team selected has won at least 1 super bowl.

Then

$Pr(M|N)=\dfrac{Pr(M\cap N)}{Pr(N)}=\dfrac{\dfrac{11\cdot 10}{C_{16}^2}}{\dfrac{C_{11}^1\cdot C_{15}^1}{C_{16}^2}}=\dfrac{110}{165}=\dfrac{2}{3}.$

3 0

3 years ago

Point m is the midpoint of ab¯¯¯¯¯ . am=2x+9, and ab=8x−50. what is the length of am¯¯¯¯¯¯ ?

iogann1982 [59]

Since m is the midpoint of ab, then the following relationship is fulfilled:
$am = \frac{ab}{2}$
Therefore, substituting values we have:
$2x+9 = \frac{8x-50}{2}$
From here, we clear the value of x.
We have then:
$2x+9 = 4x-25$
$9+25 = 4x-2x$
$34 = 2x$
$x = \frac{34}{2}$
$x = 17$
Then, the value of am, is given by substituting x in the expression:
$am=2x+9$
Substituting we have:
$am=2(17)+9$
$am=34+9$
$am=43$
Answer:
the length of am is:
$am=43$

7 0

4 years ago

The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than

pshichka [43]

Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

Let radius of the small sphere =  $x$ 

As the radius of the large sphere is double the radius of the small sphere:

Then, radius of the large sphere = $2x$

To find that how many times is the volume of the large sphere than the small sphere, we will divide the volume of large sphere by volume of small sphere:-

For smaller sphere: $Radius = x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi x^{3}$

For larger sphere: $Radius = 2x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi (2x)^{3}$

Now, we will divide volume of the larger by the smaller one:

$=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\ \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\ \times\frac{1}{x^{3} }$

$\frac{4}{3}\pi\ is \ canceled\ by\ \frac{3}{4\pi } \ and\ also\ x^{3} is\ canceled\ by \ \frac{1}{x^{3} }$

Now, we have

= $\frac{8}{1}$

Therefore, the volume of the large sphere is 8 times larger than the smaller sphere.

7 0

4 years ago

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