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uysha [10]
3 years ago
11

If w = 7 feet, x = 6 feet, y = 13 feet, and z = 8 feet, what is the area of the object?

Mathematics
2 answers:
puteri [66]3 years ago
8 0
The area to this equation is 84ft
DerKrebs [107]3 years ago
5 0

Answer:

The Area is: 84ft

Step-by-step explanation:

multiply "Y" and "X" and you get 78ft.

"W" + "?"= "Y" If "W"=7, what is 13 ("Y") - 7? 13 -7=6. so "?"=6.

"Z"-"X"="?" "Z"=8 and "X"=6. so 8-6=2

2x6=12 *but remember that to find the area of a triangle it is half of a square of rectangle so you have to divide it in half. 12/2=6.

78+6=84.

Hope this helps! :)

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3 years ago
The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

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To learn more about common differences refer to:

brainly.com/question/1486233

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