The number of students in my class went from 25 students to 30 students. What was the percent increase?
2 answers:
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Answer / Step-by-step explanation:
It should be noted that the question is incomplete due to the fact that the diagram has not been provided. However, the diagram has been complementing the question has been provided below.
To solve the question in the narrative, we recall the equation used in solving for displacement:
Thus, δₙₐ = Σ pL/AE
Where:
P is applied axial force.
E is the young's modulus of elasticity.
A is the area of cross-section.
L is length of the bar
Therefore, -8 (80) ÷ π/4 ( 0.85)² (18) (10³) + 2(150) ÷ π/4 (1.1)² (18) (10³) + 6(100) ÷ π/4 (0.45)² (18) (10³)
Solving further,
we have,
-8 (80) ÷ 0.7853( 0.85)² (18) (10³) + 2(150) ÷ 0.7853(1.1)² (18) (10³) + 6(100) ÷ 0.7853 (0.45)² (18) (10³)
= -640÷ 0.7853( 0.85)² (18) (10³) + 300 ÷ 0.7853(1.1)² (18) (10³) + 600 ÷ 0.7853 (0.45)² (18) (10³)
Solving further, we arrive at 0.111 in answer.
The positive sign indicates that end A moves away from end D.
