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Doss [256]
2 years ago
5

18. Find two numbers whose L.C.M is 3965 and G.C.F is 61​

Mathematics
1 answer:
Artist 52 [7]2 years ago
6 0

Answer:

305 and 793

Step-by-step explanation:

LCM * HCF = product

3965 * 61 = 241,865 = 5*13*61*61

HCF = 61 so

61*5 = 305

61 * 13 = 793

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Passes through the points (−4, 2) and (12, 6)?
svlad2 [7]

<u>I'll assume you need to find the equation of the line that passes through those points.</u>

Answer:

\displaystyle y-2=\frac{1}{4}(x+4)

Step-by-step explanation:

<u>Equation of a Line:</u>

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The given points are (-4,2) and (12,6), thus:

\displaystyle y-2=\frac{6-2}{12+4}(x+4)

Operating:

\displaystyle y-2=\frac{4}{16}(x+4)

Simplifying, the equation in point-slope form is:

\mathbf{\displaystyle y-2=\frac{1}{4}(x+4)}

3 0
2 years ago
1 In a test, a hybrid car drove 619 yards on 1 fluid
Aleks [24]
It’s d because u need to know how to divide
7 0
3 years ago
HELP ASAP 10 POINTSSSS
dlinn [17]
Answer:
Y= -4 :)

Steps:
Apply rule
-y + 3 = 7
Subtract 3 from both sides
-y + 3 - 3 = 7 - 3
Simplify
-y = 4
Divide both sides by -1
-y/-1 = 4/-1
Simplify
y = -4

7 0
3 years ago
Read 2 more answers
A car is driving northwest at vv mph across a sloping plain whose height, in feet above sea level, at a point nn miles north and
solong [7]
 <span>Northwest is 45 degrees north of west. If a car travels a distance x miles northwest, its northerly component gains x/sqrt(2) miles and its easterly component LOSES xsqrt(2)/ miles. 

Resultant height is h = 4500 + 100x/sqrt(2) - 75x/sqrt(2) = [25/sqrt(2)]x + 4500 
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7 0
3 years ago
Quadrilateral ABCD is transformed to create A′B′C′D′. Match the coordinates of A′ with the transformations that create it.
bulgar [2K]

Answer:

The answer is below

Step-by-step explanation:

From the image attached, the coordinates of point A is at (2, -4).

Transformation is the movement of a point from its initial location to a new position. Types of transformation include dilation, reflection, translation and rotation.

If a point A(x, y) is reflected over the x axis, the new point is at  A'(x, -y)

If a point A(x, y) is translated a units right and b units down, the new location is at A'(x + a, y - b)

If a point A(x, y) is dilated by  factor of a, the new location is at A'(ax, ay)

If a point A(x, y) is  rotated 180° clockwise about the origin, the new location is at A'(-x, -y)

Hence:

For Quadrilateral ABCD is reflected over the x-axis, the coordinates of A' is at A'(2, 4)

For Quadrilateral ABCD is translated 2 units right and 1 unit down, the coordinates of A' is at A'(4, -5)

For Quadrilateral ABCD is dilated by a scale factor of 3, the coordinates of A' is at A'(6, -12)

For Quadrilateral ABCD is rotated 180° clockwise about the origin the coordinates of A' is at A'(-2, 4).

Step-by-step explanation:

6 0
3 years ago
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