Question

Line j has an equation of y - 8 = -2/3(x+5). Line K is perpendicular to line j and passes + through (-6, -2). What is the equation of line k? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.​
(I figured it out y=3/2 x +7)

Answer 1

Answer:

y = $\frac{3}{2}$ x + 7

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

y - 8 = - $\frac{2}{3}$ (x + 5) ← is in point- slope form

with m = - $\frac{2}{3}$

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{2}{3} }$ = $\frac{3}{2}$

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept ) , then

y = $\frac{3}{2}$ x + c ← is the partial equation

to find c substitute (- 6, - 2 ) into the partial equation

- 2 = - 9 + c ⇒ c = - 2 + 9 = 7

y = $\frac{3}{2}$ x + 7 ← equation of line K