Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation
Solve for S(t):
The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:
There's no sugar in the water at the start, so (a) S(0) = 0, which gives
and so (b) the amount of sugar in the tank at time t is
As 
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
Answer:
wow
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
=(7−(−1))2+(4−4)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
=(8)2+(0)2‾‾‾‾‾‾‾‾‾‾√
=64+0‾‾‾‾‾‾√
=6‾√4
=8
Answer:
12.6
Step-by-step explanation:
To find the area of a cylinder, you find the area of the circular base and multiply it by the height. Remember that the area of a circle is pi*r^2. R, the radius, is 2. Putting this into a calculator and rounding to the nearest tenth, you get 12.6. Now that we have the circle, we multiply by the height. Since the height is 1, we have our answer of 12.6.
Absolute value is when you have either a positive or negative value within a set of "parentheses" or what look just like vertical lines and whatever is within those line stays or becomes positive. The only exception to this is when there is a negative on the outside to act upon the positive values within.
