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Sonja [21]
3 years ago
15

Balance the following equationAl + O₂ - ALO₃​

Chemistry
2 answers:
Tamiku [17]3 years ago
8 0
Answer:

2Al + 3O2 =====> 2AlO3

Explanation: this equation is wrong!!! It’s Al2O3 not AlO3
baherus [9]3 years ago
6 0

Answer:

2Al + 3O₂ ===> 2ALO₃

Explanation:

2Al + 3O₂ ===> 2ALO₃

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What is the net ionic equation for the reaction between nickle (II) chloride and silver (I) nitrate?
weqwewe [10]

Answer:

Down below

Explanation:

The following uses nickel(II) chloride

2AgNO3(aq) + NiCl2(aq) ==> Ni(NO3)2(aq) + 2AgCl(s) Molecular

8 0
3 years ago
How many atoms are in 9.95 moles of iron?
zvonat [6]

Answer:

59.92 × 10²³ atoms are in 9.95 moles of iron

1.8 ×10²² molecules are in 0.03 moles of Carbon dioxide

1.19 moles are found in 7.20 x 10^23 atoms of platinum

6 0
3 years ago
The density of whole milk 1.04 g per mL. What is the volume (in quarts) of 18.5 pounds of whole milk?
nadya68 [22]

The volume : 8,526 quarts

<h3>Further explanation</h3>

Given

The density of whole milk = 1.04 g/ml

mass = 18.5 pounds

Required

The volume

Solution

Conversion of mass

1 pound = 453,592 g

18.5 pounds = 8391,45 g

Density formula:

\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}.

Input the value :

V = m : ρ

V = 8391,45 g : 1.04 g/ml

V = 8068.7 ml

1 ml = 0,00105669 quarts

8068.7 ml =8,526 quarts

3 0
3 years ago
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
You are given 100 g of a compound. The compound is composed of 37% hydrogen and 63% oxygen. How many grams of hydrogen are prese
Reil [10]
B is the best answer
4 0
3 years ago
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