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Juliette [100K]
3 years ago
10

How to graph a line that passes through (-1,-7) and has a slope of 4

Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer:

y=4x-3

Step-by-step explanation:

First, write your equation as y=4x+b. Plug in your coordinate to the equation, it should look like this: -7=4(-1)+b. Multiply 4 by -1 to get -4. It should look like this: -7= -4+b. Add 4 to both sides to get your y-intercept of -3. Go back to your original equation and plug in -3 to b. This is your final equation: y=4x-3. Hope this helped!

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<u>7. Ans</u>;

\frac{6 {a}^{5}  {b}^{7} }{ - 2 {a}^{3} {b}^{7}  }   =  \frac{2 {a}^{3} {b}^{7}(3 {a}^{2} )  }{ - 2 {a}^{3}  {b}^{7} }  =  - 3 {a}^{2}

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<u>8. Ans</u>;

\frac{ - 20 {x}^{3}  {y}^{2} }{ - 5 {x}^{3}y }  =  \frac{ - 5 {x}^{3}y(4y) }{ - 5 {x}^{3}y }  = 4y

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<u>9. Ans</u>;

\frac{ - 16 a {b}^{4}  }{4 {b}^{3} }  =  \frac{4 {b}^{3}( - 4ab) }{4 {b}^{3} }  =  - 4ab

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<u>10. Ans;</u>

\frac{21 {m}^{8}  {n}^{5} }{27 {m}^{5} {n}^{4}  }  =  \frac{3 {m}^{5} {n}^{4}(7 {m}^{3} n)  }{3 {m}^{5} {n}^{4}(9)  }  =  \frac{7 {m}^{3}n }{9}

___o___o___

<u>11. Ans;</u>

\frac{ - 15 {x}^{5}  {y}^{4} }{45x {y}^{3} }  =  \frac{ 15x {y}^{3} ( -  {x}^{4} y)}{15x {y}^{3}(3) }  =  -  \frac{ {x}^{4}y }{3}

___o___o___

<u>12.Ans;</u>

\frac{7 {p}^{2}  {q}^{2} }{14 {p}^{2} {q}^{2}  }  =  \frac{7 {p}^{2} {q}^{2}  }{7 {p}^{2} {q}^{2} (2) }  =  \frac{1}{2}  = 0.5

I hope I helped you^_^

7 0
3 years ago
Read 2 more answers
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