All categories

2 years ago

How to graph a line that passes through (-1,-7) and has a slope of 4

Mathematics

1 answer:

lana [24]2 years ago

5 0

Answer:

y=4x-3

Step-by-step explanation:

First, write your equation as y=4x+b. Plug in your coordinate to the equation, it should look like this: -7=4(-1)+b. Multiply 4 by -1 to get -4. It should look like this: -7= -4+b. Add 4 to both sides to get your y-intercept of -3. Go back to your original equation and plug in -3 to b. This is your final equation: y=4x-3. Hope this helped!

You might be interested in

Several mountain climbers move up a mountain

Dimas [21]

Answer:

2 5/8

Step-by-step explanation:

6 0

2 years ago

What is the inverse function of f(x) = x/x-2

kherson [118]

Answer:

The answer is:

y = x/x −2

6 0

2 years ago

Read 2 more answers

I have one qt of solution diluted out 1:4 How much do I need to add to end up with a final product that’s a 1:10 solution?

LenaWriter [7]

Answer:

1.1352 L

Step-by-step explanation:

L = qt 1.0567

qt = 0.946 L

1:4 = 5

0.946/5 = 0.1892 L one part

0.1892 x 11 = 2.0812 11 parts as 1+10 =11

Answer therefore is subtracting 5 from 11 parts to get the final 6 parts added = 2.0812 - 0.946

= 1.1352 L

7 0

2 years ago

Use the identity below to complete the tasks: a3 − b3 = (a − b)(a2 + ab + b2) When using the identity for the sum of two cubes t

saveliy_v [14]

Answer:

a= $5q^ {2}$

b= $r^{2}s$

Step-by-step explanation:

Here $125q^{6}$ is like the $a^{3}$ in the general formula.

So we can write $125q^{6}$ as:

$(5q^ {2} )^{3}$

We can also write $r^{6} s^{3}$ as:

$(r^{2}s)^{2}$

Therefore:

a³= $(5q^ {2} )^{3}$

b²= $(r^{2}s)^{2}$

8 0

2 years ago

Read 2 more answers

The graph of f(x) = 2x + 3 shifts 10 units to the right when it is replaced with the graph of f(x) = 2x − k. What is the value o

Nezavi [6.7K]

Answer:

k=17

Step-by-step explanation:

Given F(x)=2x+3 shifts 10 units when it is replaced with the graph f(x)=2x-k.

The method to solve this kind of questions is find where the graph meets the x axis then add ten units to it .The obtained x coordinate is the point where the second graph meets the x axis.

Now first find where the F(x)=2x+3 meets the x axis by substituting F(x)=0.

$2x+3=0$