Side = 8m
He increases length by 2m and reduces width by 2m
(a.) New dimensions will be -
Length = 10m and Width = 6m
(b.) Area = length x breadth (or width)
here we will use the special product (x+y) (x-y)
length = (x+y) and width = (x-y)
area = (8+2) x (8-2)
8^(2) - 2^(2)
= 60
Answer:
a
Step-by-step explanation:
the answer is a. 6 faces 12 edges and 8 vertices
One red ribbon, 6 green ribbons and 3 blue ribbons total together would be 10 ribbons
Answer:
1) 270 degrees
2) pi/4 rad
Step-by-step explanation:
1.) For which value of theta is sine theta = negative 1?
Given
sintheta = -1
theta = arcsin(-1)
theta = -90degrees
Since sin is negative in the third and 4th quadrant
In the third quadrant, theta = 180 + 90 = 270degrees
In the fourth quadrant, theta = 360 - 90 = 270 degrees
Hence the required value of theta is 270degrees
2) Given the radius of the circle to be 1, the y axis value will also be 1 units
Opposite = 1
adjacent = 1
hyp = √1²+1²
hyp = √2
sin theta = opp/hyp
sin theta = 1/√2
theta = arccsin(1/√2)
theta = 45 degrees
Express in radians
45 degrees = pi/4 radians
Hence the required angle in the first quadrant is pi/4 rad
