Question

Find the surface area of the pyramid. 64in^2 56in^2 88in^2 118in^2

Answer 1

Answer:

To find the surface area of this pyramid, we must find the area of one triangle flap which we then multiply by 4 because there are 4 of those equal triangle flaps surrounding the base(square). Once we find the area of those triangles, we then find the base(square)'s area. Next, we add all those areas together to get the result of the surface area.

Formula for area of triangle;

A = BH x 1/2

Where 'B' represents the base, 'H' represents the height, and 1/2 is just dividing the product of those two lengths by 2.

Plug in what you know, given that the base of one triangle is 4, and the height is 6.

A = 4(6) x 1/2

A = 24 x 1/2

A = 24/2

A = 12, the area of one triangle is 12 inches.

Now, we find the area of all the triangles by multiplying the area of one triangle by 4.

12 = Area of triangle

4 triangles in total, so:

12(4)

= 48 inches is the area of all the triangles.

Now we find the area of the base(square) using the formula;

(vol of square formula)
A = $s^{2}$

Where 's' represents one side of the square which is being squared.

or

A = l · w

Where 'l' represents the length and 'w' represents the width.

Plug in what you know, given that one side of the square is 4 inches (as well as the length and width).

(I'll be using the formula $s^{2}$)

A = $s^{2}$

A = 4^2 ← (The symbol ' ^ ' means raised to the power of.)

A = 16, the area of the base(square) is 16 inches.

Now we add both areas together:-

48 + 16

= 64 inches^2 is the surface area, your answer is A.