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olga nikolaevna [1]
2 years ago
10

Find the surface area of the pyramid. 64in^2 56in^2 88in^2 118in^2

Mathematics
1 answer:
ziro4ka [17]2 years ago
5 0

Answer:

To find the surface area of this pyramid, we must find the <u>area</u> of one <u>triangle</u> flap which we then <u>multiply by 4</u> because there are 4 of those equal triangle flaps surrounding the base(square). Once we find the area of those triangles, we then find the <u>base(square)'s area</u>. Next, we add all those areas together to get the result of the surface area.

Formula for area of triangle;

A = BH x 1/2

Where 'B' represents the base, 'H' represents the height, and 1/2 is just dividing the product of those two lengths by 2.

Plug in what you know, given that the base of one triangle is 4, and the height is 6.

A = 4(6) x 1/2

A = 24 x 1/2

A = 24/2

A = 12, the area of <em>one triangle is 12 inches</em>.

Now, we find the area of all the triangles by multiplying the area of one triangle by 4.

12 = Area of triangle

4 triangles in total, so:

12(4)

= <u>48 inches</u> is the <u>area</u> of <u>all the triangles</u>.

Now we find the area of the base(square) using the formula;

(vol of square formula)
A = s^{2}

Where 's' represents one side of the square which is being squared.

or

A = l · w

Where 'l' represents the length and 'w' represents the width.

Plug in what you know, given that one side of the square is 4 inches (as well as the length and width).

(I'll be using the formula s^{2})

A = s^{2}

A = 4^2 ← (The symbol ' ^ ' means raised to the power of.)

A = 16, the <u>area</u> of the <u>base(square)</u> is <u>16 inches</u>.

Now we add both areas together:-

48 + 16

= <u>64 inches^2</u> is the surface area, your answer is A.

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