Answer with explanation:
The Given Inequality is
|x-4|<9
Modulus of a number yields always a positive value.
→|x-4|= x-4, when, x-4≥0
That is , x≥4.
= -(x-4), when, x-4<0
means, x<4.
it can be Written as
→ -9<x-4<9
→ -9+4 < x -4+4 < 9+4
→ -5<x<13
→x∈(-5,13)
The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
F(11) means to replace x in the equation with 11
12(11) + 5
12 x 11 = 132
Now you have 132 + 5 = 137
F(11) = 137
it's 45
Step-by-step explanation:
Okay, so if 2 peppers is 25 meters long, you just divide 25 by 2 to get how many peppers the dragon breathes as 1 pepper. So then you get 12.5, And if you do that with the green peppers, you get 1.5. So, the dragon ate 3 green peppers, so it's 12.5 x 3 , aka. 12.5+12.5+12.5. That's 37.5, and if you do 1.5x5 for the green peppers, it's 7.5, And now you add 37.5+7.5, and you get 45.
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
