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3241004551 [841]
2 years ago
15

Can someone please help me with this question?

Mathematics
2 answers:
Anna007 [38]2 years ago
8 0

\qquad\qquad\huge\underline{{\sf Answer}}

As per the given graph we can observe the number of students which watched TV for certain intervals.

According to question, we have to find the common interval of minutes students spent watching TV~

That means : we have to find the time interval in which most of the students prefer to watch TV ~

Hence, the most common interval is :

\qquad \tt \dashrightarrow \:150 - 179 \:  \:  \: minutes

MrRissso [65]2 years ago
4 0

Answer:

150-179 minutes

Step-by-step explanation:

The most common interval (the tallest graph) of minutes students spent watching watching TV?

The correct answer should be 150-179 minutes because it's the most common, meaning that a lot of students spent 150-179 minutes watching TV.

Hope this helps!

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Which inequality is equivalent to |x-4|<9
Lorico [155]

Answer with explanation:

The Given Inequality is

  |x-4|<9

Modulus of a number yields always a positive value.

→|x-4|= x-4, when, x-4≥0

                     That is , x≥4.

         = -(x-4), when, x-4<0

                    means, x<4.

     it can be Written as

 → -9<x-4<9

→ -9+4 < x -4+4 < 9+4

→ -5<x<13

→x∈(-5,13)

8 0
3 years ago
Read 2 more answers
NO SCAM PLEASEEEE
damaskus [11]
The answer is 11/36

2/12 chance of rolling fours

because there are 2 sides containing a four on both dice combined and 12 sides in total.

Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.

I personally like to imagine a box like this:
_ _ _ _ _ _
|
|
|
|
|
|

If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.

1/6 * 1/6 = 1/36 chance to roll double of ones

And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:

1/36 * 5 = 5/36

So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:

5/36 + 2/12 =

5/36 + 6/36 =

11/36
5 0
3 years ago
HELP ASAP PLSS!<br><br><br> f(x) = 12x + 5<br><br> find f(11)<br><br><br> f(11) =
loris [4]

F(11) means to replace x in the equation with 11

12(11) + 5

12 x 11 = 132

Now you have 132 + 5 = 137

F(11) = 137

5 0
4 years ago
A dragon likes to eat red peppers and green peppers because they help him breathe fire. If the dragon eats 2 red peppers, he can
N76 [4]

it's 45

Step-by-step explanation:

Okay, so if 2 peppers is 25 meters long, you just divide 25 by 2 to get how many peppers the dragon breathes as  1 pepper. So then you get 12.5, And if you do that with the green peppers, you get 1.5. So, the dragon ate 3 green peppers, so it's 12.5 x 3 , aka. 12.5+12.5+12.5. That's  37.5, and if you do 1.5x5 for the green peppers, it's 7.5, And now you add 37.5+7.5, and you get 45.

4 0
2 years ago
Shureka Washburn has scores of 67​, 68​, 76​, and 63 on her algebra tests. a. Use an inequality to find the scores she must make
mash [69]
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76

b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.


8 0
3 years ago
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