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Ivenika [448]
3 years ago
10

WILL MARK AS BRAINLIEST

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0

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-12xy^3z^5+15x^2z factor
azamat

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Which equation below would be perpendicular to the line y = 2?
nadya68 [22]
Answer:
A) y=1/5x
Step-by-step explanation:
Coz, the way you identify a perpendicular line is by looking for its negative reciprocal. The neagtive reciprocal of 5= 1/5
Now, to check the ans we can multiply the negative reciprocal by "m"
(m in y=mx+c or y=mx+b)
in this case the "m" is stated as 5, so all we need to do is 1/5*5 if the ans is 1 then your ans is right....and over here it is
So thats how you identify & check perpendicular lines!
3 0
2 years ago
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. The product of 4.7 and 6.5 equals 30.55. What is the product of 4.7 and 4.7 and
7nadin3 [17]
The answer is 3.5 & 355 because the decimal shifts to the left or right, you move the decimal in the answer too.
4 0
3 years ago
Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two
In-s [12.5K]
Let the original 2-digit number be xy.
Because 5 times the sum of the digits is 13 less than the number, therefore
5(x + y) = 10x + y - 13 
5x + 5y = 10x + y - 13
-5x + 4y = - 13             (1)

The number with reversed digits is yx.
Because 4 times the sum of the digits is 21 less than the reversed 2-digit number, therefore
4(x + y) = 10y + x - 21
4x + 4y = 10y + x - 21
3x - 6y = -21
x - 2y = -7
x = 2y - 7                 (2)

Substitute (2) into (1).
-5(2y - 7) + 4y = -13
-10y + 35 + 4y = -13
-6y = -48
y = 8

From (3), obtain
x = 2*8 - 7 = 9

Answers:
The original 2-digit number is 98
The reversed 2-digit number is 89
The difference between the original and the reversed 2-digit numbers is
98 - 89 = 9
4 0
3 years ago
Given F(x) =3x^2 - 4 and F(a) = 8 find a
Bogdan [553]

F(x)=3x^2-4\\\\F(a)=8\to3a^2-4=8\qquad\text{add 4 to both sides}\\\\3a^2=12\qquad\text{divide both sides by 3}\\\\a^2=4\to a=\pm\sqrt4\to a=\pm2\\\\Answer:\ \boxed{A.\ \pm2}

5 0
3 years ago
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