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anygoal [31]
3 years ago
7

Can some one solve this

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0
Well, first you have to convert to one unit... then simplify
D:H
150m:16500cm
150m:160m
150:160
30:33
10:11
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pochemuha

This is the isosceles triangle. Therefore, the angles at the base are congruent.

We know that the sum of the measures of the angles in a triangle is 180°.

Therefore we have the equation:

38^o+x^o+x^o=180^o

38^o+2x^o=180^o        <em>subtract 38 from both sides</em>

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The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

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We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

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In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

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