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anygoal [31]
4 years ago
7

Can some one solve this

Mathematics
1 answer:
Roman55 [17]4 years ago
7 0
Well, first you have to convert to one unit... then simplify
D:H
150m:16500cm
150m:160m
150:160
30:33
10:11
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WILL GIVE BRAINLIEST!!!​
Dahasolnce [82]

Answer:

(3/4)*x

Step-by-step explanation:

Dilation really means  the multiply the scale factor  to every segment of the original figure or shape to get the new transformed figure.

so  (3/4) * (segment lengths) = (new segment lengths)

5 0
3 years ago
I need help solving the picture below please
lesya [120]

Answer:

x = 3

Step-by-step explanation:

From the given parallelogram;

m<XWC = m<XYC

Given

m<XWC = 2x+5

m<XYC = 3x+2

Equate

2x+5 = 3x+2

2x - 3x = 2 - 5

-x = -3

x = 3

Hence the value of x is 3

6 0
3 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
Help these problems lol alll of them
Ratling [72]

Answer:

1) 18

2) Tuesday, Thursday, Saturday

3) Weeks 2 and 4



7 0
3 years ago
There are 20 runners in a race for 1st, 2nd, 3rd, and 4th place. How many different arrangements can be made?​
Setler [38]

Answer: 160

Step-by-step explanation:

3 0
2 years ago
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