Okay, so I really hope that you can read all my work. I just spent the last 45 mins doing this problem as neatly as possible with as much detail as possible. So, I really hope my work doesn't confuse you.
My Final Answers were:
JI= 40 units (found using the Pythagorean theorem)
IM= 66.66 units = 66 and 2/3rds (found by dividing the length of JL by the cosine of ∠JIM )
LM=42.66 units = 42 and 2/3rds (found by IM= 24+LM; solve for LM since we know IM=66.66)
JM= 53.33 units= 53 and (1/3rd) (found by using the Pythagorean theorem; this time using JI as "a" and IM as c)
Hope this helped and all made sense!
(Pythagorean theorem is a²+b²=c²)
i write everything in the exploration
Step-by-step explanation:
MN=31
KN=45
K=61°
L=119°
M=61°
CF=10
FE=15
CE=14
GD=11
QR=19
SR=24
PT=21
SQ=20
QRS=70°
PQS=53°
RPS=35°
PSQ=53°
7x-2=12x-22
-2=5x-22
20=5x
x=4
7×4-2=26 (12×4-22=26)
(2x+11)×2=8x-14
4x+22=8x-14
22=4x-14
36=4x
x=9
( (2×9+11)×2=58. 8×9-14=58. so it's correct)
(3x+5)+(9x-17)=180
12x-12=180
12x=192
x=16
( (3×16+5)+(9×16-17)=53+127=180 so it's correct)
10x-27=2x+29
8x-27=29
8x=56
x=7
10×7-27=43 (2×7+29=43)
V=180-43°=137°
Answer: -124
Step-by-step explanation: -83-41
subtract and it suppose to give you -124
Answer:
False
Step-by-step explanation:
The statement is False, because the average value of a funciton f(x) on an interval is given by the value of the integral of the function on that interval divided by its length. In this case, the integral is right, but we are not integrating exactly f, and thats why the average value is not given correctly.