3 years ago

Rewrite the expression as an equivalent power with a negative exponent. a. 1/49 b. 27/125

1 answer:

3 0

$\dfrac{1}{49}=\left(\dfrac{1}{7}\right)^2=7^{-2}\\
\dfrac{27}{125}=\left(\dfrac{3}{5}\right)^3=\left(\dfrac{5}{3}\right)^{-3}$

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