Question

Rewrite the expression as an equivalent power with a negative exponent. a. 1/49 b. 27/125

Answer 1

$\dfrac{1}{49}=\left(\dfrac{1}{7}\right)^2=7^{-2}\\ \dfrac{27}{125}=\left(\dfrac{3}{5}\right)^3=\left(\dfrac{5}{3}\right)^{-3}$