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ruslelena [56]
2 years ago
14

Determine and state an equation of the line perpendicular to the lines 5x-4y=10 and passing through the point (5,12). in point-s

lope form.
Please help I will mark branilest!!! and give 100 points
Mathematics
1 answer:
sergey [27]2 years ago
8 0
Perpendicular lines have slopes that are negative reciprocals of one another.

slope intercept form (y = mx + b) of the first equation will help us find the slope of the first line: where m = slope

5x-4y=10
-4y=-5x + 10
y=-5/-4 x + 10/-4
y=5/4 x -2.5

if the slope of this line is 5/4 then the slope of the perpendicular line is -4/5.

Therefore with the given information we can state the equation of the second line in point slope form (y-y,) = m(x-x,)

the coordinates of (5,12) can are substituted for x, and y,

so the answer is

(y-12) = -4/5(x-5)

I hope this helped and is BRAINLIEST!

Good luck with your studies!

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Analyze the diagram below and complete the instructions that follow. Find the area of QRS.
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<u>Answer-</u>

<em>The area of QRS is </em><em>238.7</em><em> sq units.</em>

<u>Solution-</u>

According to properties of supplementary angles,

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Then the area of the triangle will be,

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=238.7\text{sq.units}

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