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Masteriza [31]
3 years ago
10

Find the 9th term of the geometric sequence whose common ratio is 2/3 and whose first term is 8

Mathematics
1 answer:
velikii [3]3 years ago
8 0

Answer:

0.3121

Please Mark Brainliest If This Helped!

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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Juli2301 [7.4K]

Answer:

4/8

Step-by-step explanation:

8 is how many cookies in total and 4 is how many that needs to be distributed.

7 0
3 years ago
DOUBLE POINTS for answering the two questions
Margarita [4]

Answer:

i have the same question

Step-by-step explanation:

6 0
3 years ago
Write the equation of the circle with center (−1, −3) and (−7, −5) a point on the circle.
Pepsi [2]
So, we know the center is at -1, -3, hmmm what's the radius anyway?

well, the radius will be the distance from the center to any point on the circle, it just so happen that we know -7, -5 is on it, thus

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -1 &,& -3~) 
%  (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2}
\\\\\\
r=\sqrt{36+4}\implies r=\sqrt{40}\\\\
-------------------------------

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad 
radius=\stackrel{\sqrt{40}}{ r}
\\\\\\\
[x-(-1)]^2+[y-(-3)]^2=(\sqrt{40})^2\implies (x+1)^2+(y+3)^2=40
5 0
3 years ago
Help!!! (Tell me if you can’t see it clearly)
meriva
I believe it’s option c!
3 0
2 years ago
Is 32.5 greater or less than 30.8<br><br>PLEASE HELP QUICKLY AS POSSIBLE THANK YOU :)​
ivann1987 [24]

Answer:

32.5 is greater than 30.8

6 0
3 years ago
Read 2 more answers
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