Question

A 25 ft. ladder resting against the side of a building forms a right triangle with the ground. The bottom of the ladder is 7 ft. away from the base of the building.
How far up the side of the building does this ladder reach?
I care more about your explanation than the answer so try to do that for me :)

Answer 1

Answer:

The correct answer is 24

Step-by-step explanation:

to solve this you will need to use the pathagreom theorum

a^{2}+b^{2}=c^{2}

A= one side lenth

B= the secons side lenth

C= hypotnuse

It is helpfull to draw out the situation

you know that the latter is 25 ft, that is your hypotnuse

you also know that the 7 ft away from the base of the building is one of the side lenths, lets call it side a

so plug the numbers into the equation

7^2 + b^2 = 25 ^2

you leave b^2 alone because that is the side you are trying to find

now square 7 and 25 but leave b^2 alone

49 + b^2 = 625

now subtract 49 from both sides

b^2 = 576

now to get rid of the square of b you have to do the opposite and square root both sides removing the square of the B and giving you the answer of..........

B= 24

Hope this helped!! I tryed to explain it as simpil as possiable

Answer 2

Correct answer. 24. why? the guy explained it perfectly up there!