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castortr0y [4]
3 years ago
9

Solve the system by graphing.

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Option A: (0,2) is the correct answer

Step-by-step explanation:

the given equations are linear equation.

System of linear equations can be solved by graphing. The graph of equations are in the form of lines, the solution of the equations is the point of intersection of both lines

Given equations are:

y = x+2\\y = -2x+2

We have used the online graphing calculator "desmos" to plot the lines (Picture Attached)

The lines intersect at: (0,2)

Hence,

Option A: (0,2) is the correct answer

Keywords: Linear equations

Learn more about linear equations at:

  • brainly.com/question/750742
  • brainly.com/question/7419893

#LearnwithBrainly

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You can buy 15 stickers for $10 how much would 12 stickers cost
Readme [11.4K]

Answer:

8 dollars

Step-by-step explanation:

We can write a ratio to solve

15 stickers            12 stickers

------------------ = ----------------------

10 dollars           x dollars

Using cross products

15 *x = 12 * 10

15x = 120

Divide each side by 15

15x/15 = 120/15

x =8

8 dollars

4 0
2 years ago
Read 2 more answers
Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A<br>What is the value of the A^2?<br><br>​
Alla [95]

\large \mathbb{PROBLEM:}

\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}

\large \mathbb{SOLUTION:}

\!\!\small \begin{array}{l} \displaystyle \sf A = \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx \\ \\ \textsf{Simplifying} \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\sec^2 x - 1}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\tan^2 x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\cdot \dfrac{\sqrt{\tan x}}{\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\tan x}{\sin 2x\ \sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{\sin x}{\cos x}}{2\sin x \cos x \sqrt{\tan x}}\ dx\:\:\because {\scriptsize \begin{cases}\:\sf \tan x = \frac{\sin x}{\cos x} \\ \: \sf \sin 2x = 2\sin x \cos x \end{cases}} \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{1}{\cos^2 x}}{2\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sec^2 x}{2\sqrt{\tan x}}\ dx, \quad\begin{aligned}\sf let\ u &=\sf \tan x \\ \sf du &=\sf \sec^2 x\ dx \end{aligned} \\ \\ \textsf{The integral becomes} \\ \\ \displaystyle \sf A = \dfrac{1}{2}\int \dfrac{du}{\sqrt{u}} \\ \\ \sf A= \dfrac{1}{2}\cdot \dfrac{u^{-\frac{1}{2} + 1}}{-\frac{1}{2} + 1} + C = \sqrt{u} + C \\ \\ \sf A = \sqrt{\tan x} + C\ or\ \sqrt{|\tan x|} + C\textsf{ for restricted} \\ \qquad\qquad\qquad\qquad\qquad\qquad\quad \textsf{values of x} \\ \\ \therefore \boxed{\sf A^2 = (\sqrt{|\tan x|} + c)^2} \end{array}

\boxed{ \tt   \red{C}arry  \: \red{ O}n \:  \red{L}earning}  \:  \underline{\tt{5/13/22}}

4 0
2 years ago
Please answer this ASAP
Amanda [17]

Answer: 2x and y= 4+

Step-by-step explanation:

x = 2 times 2 and so on....

y = 4 plus 4 plus 4 etc....

3 0
3 years ago
What is 5:1 as a fraction?
vodomira [7]
The fraction would be 5/1.
7 0
3 years ago
Read 2 more answers
Please solve and show step by step
MissTica
The answer to the question

8 0
3 years ago
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