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Sauron [17]
3 years ago
13

Can someone help me please.​

Mathematics
1 answer:
wolverine [178]3 years ago
5 0

9514 1404 393

Answer:

  a=\sqrt{33}

Step-by-step explanation:

The Pythagorean theorem tells you that the area of the square with side 'a' is the difference of the areas of the other two squares.

  a² = 7² -4²

  a² = 49 -16 = 33

  a = √33

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Find the solutions of the quadratic equation 3x^2-4x+4=0
julia-pushkina [17]

Answer:

2.3

Step-by-step explanation: if your finding the decimal 2.3 will be your answer if not then sorry

8 0
2 years ago
Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
Point Q is the image of Q (-5,1) under a translation by 6 units to the right and 2 units down.
Alex787 [66]

Answer:

(1,-1)

Step-by-step explanation:

The graph is being shifted 6 units to the right which affects the x-value and it is also being affected 2 units down which affects the y-value.

6 0
3 years ago
3x-8 i nedd help finding what x represent
seropon [69]

8/3

divide both sides by 3 and you get x=8/3

7 0
3 years ago
What is the range of the function represented by this graph? the graph of a quadratic function with a minimum value at the point
tatiyna

Answer:

see explanation

Step-by-step explanation:

The minimum is at the vertex (- 3, 1 ), that is y = 1

Since the graph is a minimum then it opens vertically up U

The range of the values of y are therefore

range [ 1, ∞ )

7 0
3 years ago
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