The answer to ur problem is 1.27945
CD is called the middle base and is equal to :(AB + EF)/2
CD = <span>(AB + EF)/2
4x = [(x</span>²+10) + (8-x)]/2
8x = x²+10+8-x
8x= x²-x+18
x²-9x+18 = 0
x' = [-b+√(b²-4.a.c)]/2a & x" = [-b-√(b<span>²-4.a.c)]/2a
x'= 6 and x" = 3, So we have2 values of x</span>
So it's best in this case to separate both shapes so you have a rectangle and a triangle so to solve the area of a rectangle you do
The following ( picture )
So I hope this helps
So a triangular prisim is like a triangle stacked on top of x number of identical triangles making a height, like a piece of paper made into a stack
so
basically find the area of each side and add
look at diagram/attachment
find area of triangle
1/2 b times h= area of 1 triangular face
multiply by 2 because 2 sides so 1/2 times 2 b times h=b times h
then 3 other sides
find area of each side and add
areas=(H times B)+(H times c)+(H times a)
so SA=(b times H)+(H times B)+(H times c)+(H times a)